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Sailing in tide..quiz.

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iGRF View Drop Down
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    Posted: 04 Oct 17 at 10:41am
Tide can and does lift on both tacks.

It just doesn't lift in the same manner as a windshift lift which is what you and your maths fail to grasp.
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Post Options Post Options   Quote Guests Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 10:04am
Originally posted by iGRF

Now now, don't go getting above yourself, some of what you say here is true, but your start line scenario was wrong, and so is your assertion that boards and boats being more or less affected by the tide.

I pointed out earlier, a cross tidal vector can induce a board onto the plane, the same vector would never induce planing in something like your RS200, ergo the lighter board would seek out sectors of a course where tidal lee bow were stronger.

The start line scenario isn't wrong. I clearly showed it was true and backed it up withe maths. That you still argue otherwise or can't comprehend it is another thing. 

Yes, a tidal increase in wind can lift a board on to the plane. And it can and does an RS200 as well. 

What you fail to realise is that when the tide shifts the apparent wind it shifts it in one direction (which should be obvious, it can't lift both tacks, or head both tack). This will favour one tack or the other. When the tide increases the apparent wind it increases it does so for both tacks. 

So in the board race you described, where the current lifted you and increased the apparent wind allowing you to plane. That's fine. But, the increase in apparent would have also been enough for the board on starboard to plane. It's just that they would be on a header and you were on a lift. 


Edited by mozzy - 04 Oct 17 at 10:08am
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Post Options Post Options   Quote iGRF Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 9:57am
Originally posted by mozzy




]Now, add in wind. all boat are still effected just the same by tide (this is where iGRF is wrong about board being more or less effected by being lighter or having less hull in the water or whatever). The tidal vector is the same for all boats.



Now now, don't go getting above yourself, some of what you say here is true, but your start line scenario was wrong, and so is your assertion that boards and boats being more or less affected by the tide.

I pointed out earlier, a cross tidal vector can induce a board onto the plane, the same vector would never induce planing in something like your RS200, ergo the lighter board would seek out sectors of a course where tidal lee bow were stronger.


I have another scenario for you to consider, in your {doesn't make any difference which angle the boat is to the tide) assumptions.

Lets take the typical triangle with a cross tide, but the 1st leg has been set broad and the return leg of the triangle is tight.

The advantageous cross tide assists on the 1st leg, but is disadvantageous on the 2nd.

It is still a reach though but the wind is failing

Boat A gybes and sails for the mark with the tide still on the weather side of the foils.

Boat B gybes higher and presents the bow directly into the tidal flow.

Who gets to the lee mark first?

Edited by iGRF - 04 Oct 17 at 10:00am
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Post Options Post Options   Quote Sam.Spoons Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 9:54am
Originally posted by mozzy

Sam, I take your point, but if you really want to be a pedant, then wind resistance moving a boat through the water = sailing. To be totally becalmed in tide, the true wind would need to have an equal vector to the tide, to cancel out (i.e same direction and strength). I.e wind felt on the water is zero = flat calm.

I very nearly added the following to my previous post the decided it was stating the obvious :-

"And most boats will sail pretty effectively in 3 knots of wind"   LOL


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Post Options Post Options   Quote Guests Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 9:35am
Sam, I take your point, but if you really want to be a pedant, then wind resistance moving a boat through the water = sailing. To be totally becalmed in tide, the true wind would need to have an equal vector to the tide, to cancel out (i.e same direction and strength). I.e wind felt on the water is zero = flat calm. 

All boats are affected the same by tide, here is why:
A2Z; ask yourself this. When it's a flat calm on the lake, do the boats move through the water? The boats aren't rigidly attached to the water on a lake, but if they are becalmed they don't move. You don't see water flows past and hydrodynamic forces moving boat through the water on a lake do you? 

So if you accept all boats becalmed on a lake sit still,  then why would they move through water when becalmed in a current? If there is no force to propel the boat through the water they will sit still, apparently attached to the water and from the shore the boat will appear to move with the tide. 

Now, add in wind. All boats are still affected just the same by tide (this is where iGRF is wrong about boards being more or less effected by being lighter or having less hull in the water or whatever). The tidal vector is the same for all boats. 
Now; when boats move faster, their vector through the water will be greater but crucially tidal vector remains the same. So it's more accurate to say: "all boats fast or slow are affected the same by current over time, however faster boats which cover more ground in a set time are less affected by current over a set distance". 

All boats are affected the same by tide over time, but faster boats spend less time being affected...
Some boats may move faster through the water, but not because they are 'cutting through the tide better', but simply because they are cutting through the water better. They are just a faster boat. 

Now, this is where things do get interesting, if you're still following me. We race around marks which are fixed to the ground. If all boats raced against the tide for 60 minutes all boats would experience 60 minutes of tide, regardless of how fast they are: simple. If there was 1 knot of tide, all boats, no matter how fast or slow, will be moved 1 nautical mile by the tide in those 60 minutes.  

However, we don't race for set times, we race over set distances fixed to the land. Faster boats spend less time going around the course, so spend less time being affected by the tide. 

This phenomena is called the 'tidal gate'. If you go from a favourable tide to an unfavourable tide the time between boats on the water will reduce. The opposite is true is you go from unfavourable to favourable.  You will notice this most when beating against the tide. The lead boats round the windward mark and accelerate away stretching out a large lead over the water. When they head up round the leeward mark, the pack appear to catch them back up as the leader hits the unfavourable tide.

But, if faster boats spend less time in the unfavourable tide, they'll also spend less time in favourable tide, so it will even out won't it? No, it doesn't and here's why: 
The net tide is always unfavourable, if you finish roughly where you started. This is because when the tide is against you it will make the leg feel longer, and when it is with you it will make the leg shorter. So around the whole course, you'll spend more time in unfavourable tide. 
This is why HISC adjusts handicaps, as on any given day faster PY boats, over a set distance course, experience less tide (and tide is always net unfavourable) giving faster boats an advantage. However, as the tide is always different (either itself or compared to the wind) it means the magnitude of the advantage for faster boats speed is constantly changing. Therefore there can never can be one fixed PY. 
Also, slow boats aren't equally slow / fast on all legs. Some boats are better at reaching, or beating, or fetching. The PY would also need to account for which legs the tide was unfavourable, and how this matched against the boats strength on these legs. 

Complicated enough for you? 


Edited by mozzy - 05 Oct 17 at 4:06pm
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Post Options Post Options   Quote Sam.Spoons Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 8:49am
Surely, in a flat calm, as soon as the boat starts to drift with the current an apparent wind equal to the speed of the current will be generated? E.g. in a 3 knot tide with no actual wind (as measured by an anchored boat) any boat drifting with the current will feel a 3 knot breeze?
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Post Options Post Options   Quote sargesail Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 7:41am
But the wind resistance is just the gaseous fluid motion bit of the vector.

In a flat calm the rate of drift is the same.  Seen it in the Cherbourg Race couple of years ago.  Heaps of different boats drifting together.  Possibly you could have assessed that the much heavier ones had momentum and took longer to start drifting the other way when the tide turned.

Or that might have been the beer we were drinking for breakfast..... 
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Post Options Post Options   Quote 423zero Quote  Post ReplyReply Direct Link To This Post Posted: 04 Oct 17 at 7:25am
They don't, amount of boat in water, plus wind resistance, handicap fleet, different boats react differently.
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Post Options Post Options   Quote Guests Quote  Post ReplyReply Direct Link To This Post Posted: 03 Oct 17 at 10:51pm
As a pondie I'm clueless but intrigued.
Boats aren't rigidly attached to the water, the water flows past and hydrodynamic forces are imparted.  I can't see why they should be the same regardless of the type of boat, in which case I can't see why they drift off at the same (current) speed. Therefore, if not all boats slip at 1.5kts in the example above, the winning tactics might not always be the same?
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Post Options Post Options   Quote Sam.Spoons Quote  Post ReplyReply Direct Link To This Post Posted: 03 Oct 17 at 10:38pm
In a flat calm that must the case (well actually won't they drift slightly slower than the tide due to air resistance)? TBF that might slow them by a fraction of a knot........ "Pedant's rule OK?"
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